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4.9x^2+8x-0.5=0
a = 4.9; b = 8; c = -0.5;
Δ = b2-4ac
Δ = 82-4·4.9·(-0.5)
Δ = 73.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{73.8}}{2*4.9}=\frac{-8-\sqrt{73.8}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{73.8}}{2*4.9}=\frac{-8+\sqrt{73.8}}{9.8} $
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